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SELECT Owner_id,COUNT(Owner_id) AS HYGS into #ls FROM BEFRIEND WHERE
Friend_id IN (select Friend_id from BEFRIEND where Owner_id='A') --与A共同好友关系的人
AND Friend_id!='A' --与A非好友关系
order by HYGS desc
select top 10 * from SITEUSER where Id in(select * from #ls)