C语言编程 帮忙做一下
发布网友
共3个回答
热心网友
这个好做，慢慢来啊，先占位
输入数时，之间用空格！！！！！
//1. 实现两个整数的 交换
#include<stdio.h>
main()
{
int a,b,t;
scanf("%d %d",&a,&b);
printf("交换前数为:%d %d\n",a,b);
t=a;
a=b;
b=t;
printf("交换后的数为:%d %d",a,b);
}
//2.实现两个整数相加
#include<stdio.h>
main()
{
int a,b,sum;
scanf("%d %d",&a,&b);
printf("两数为:%d %d\n",a,b);
sum=a+b;
printf("其和为:%d",sum);
}
//3.实现3个数之间大小的比较，把最大的 数输出 ;
#include<stdio.h>
main()
{
int a,b,c,max,min;
scanf("%d %d %d",&a,&b,&c);
printf("三个数为:%d %d %d",a,b,c);
max=a>b?a:b;
max=max>c?max:c;
min=a<b?a:b;
min=min<c?min:c;
printf("最大数为：%d,最小数为:%d",max,min);
}
//4.实现10个数之间大小的比较，输出最大值和最小值
#include<stdio.h>
main()
{
int max,min,i;
int q[11];
for(i=0;i<9;i++)
scanf("%d",&q[i]);
for(i=0;i<9;i++)
printf("%4d",q[i]);
max=q[0];
min=q[0];
for(i=1;i<9;i++)
{if(max<q[i]) max=q[i];
if(min>q[i]) min=q[i];
}
printf("最大数为:%d,最小数为:%d",max,min);
}
完成！！！！！！！！！！
兄弟，我可是自己 编！！！得啊！！
热心网友
/*#include <stdio.h>
#include <string.h>
void main(){
int j,l=0;
int a[200][2];
int str;
for(;l<200;){
str=getchar();
if(str=='#')break;
for(j=0;j<l;j++){
if(a[j][1]==str){a[j][0]++;l--;goto ens;}
}
a[l][0]=1;
a[l][1]=str;
ens:l++;
}
}
//for(j=0;j<l;j++)printf("%c %d\n",a[j][1],a[j][0]);
}*/
#include <stdio.h>
void swap(int *a,int *b){
int t;
t=*a;
*a=*b;
*b=t;
}int sum(int a,int b){
return(a+b);
}
void B3(double a,double b,double c){
if(a>b){
if(a>c)printf("%lf\n",a);
else printf("%lf\n",c);
}else{
if(b>c)printf("%lf\n",b);
else printf("%lf\n",c);
}
}void B10(double a[]){
int i;
double s,p;
s=a[0];
p=a[0];
for(i=1;i<10;i++){
if(a[i]>s)s=a[i];
if(a[i]<p)p=a[i];
}printf("%lf %lf\n",s,p);
}void main(){
int a=3,b=5,c=7;
double d[10]={1,2,3,4,5,6,7,8,9,10};
swap(&a,&b);
printf("%d %d %d\n",a,b,sum(a,b));
B3(5.1,3.2,10.3);
B10(d);
}
热心网友
#include <stdio.h>
void swap(int& a, int& b)
{
int temp = a;
a = b;
b = temp;
}
int sum(int a, int b)
{
return a+b;
}
int Max(int a, int b)
{
return (a > b? a : b);
}
int Min(int a, int b)
{
return (a < b? a : b);
}
int main()
{
int a[10] = {9,8,7,6,5,4,3,2,1,0},b;
printf("%d %d ", a[0], a[1]);
swap(a[0], a[1]);
printf("%d %d\n", a[0], a[1]);
b = sum(a[0], a[1]);
printf("sum of a[0] and a[1] is: %d\n",b);
b = Max(a[0],Max(a[1],a[2]));
printf("max of a[0], a[1] and a[2] is: %d\n", b);
b = Max(Max(Max(Max(Max(Max(Max(Max(Max(a[0],a[1]),a[2]),a[3]),a[4]),a[5]),a[6]),a[7]),a[8]),a[9]);
printf("max of a[0] to a[9] is: %d\n", b);
b = Min(Min(Min(Min(Min(Min(Min(Min(Min(a[0],a[1]),a[2]),a[3]),a[4]),a[5]),a[6]),a[7]),a[8]),a[9]);
printf("min of a[0] to a[9] is: %d\n", b);
return 0;
}
