f(x)=lnx展开成x-2的幂级数
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先求导f'(x)=1/x,1/x=1/[(x-2)+1]+1=1-[(x-2)+1]+[(x-2)+1]^2-[(x-2)+1]^3.....+(-1)^n*[(x-2)+1]^n+.....
两边逐项积分得f(x)=[(x-2)+1]-[(x-2)+1]^2/2+[(x-2)+1]^3/3+.....+(-1)^n[(x-2)+1]^n/(n+1)+......,
