...在z=f(x,y) 由方程F(U.V)=0 确定,其中 U=x+y+Z,v=x^2+y^2+z^2...
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dF/dx=(dF/du)*(du/dx)+(dF/dv)*(dv/dx)=dF/du+（dF/dv）*2x
dF/dy=(dF/du)*(du/dy)+(dF/dv)*(dv/dy)=dF/du+（dF/dv）*2y
dF/dz=(dF/du)*(du/dz)+(dF/dv)*(dv/dz)=dF/du+（dF/dv）*2z
所以
dz/dx=-(dF/dx)/(dF/dz)
dz/dy=-(dF/dy)/(dF/dz)
